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Standard XII

Physics

Stefan-Boltzman's Law

A metal ball ...

Question

A metal ball of surface area $200 c m^{2}$ and temperature $527^{o} C$ is surrounded by a vessel at $27^{o} C$ . If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is $(ρ = 5.67 \times 10^{- 5} J / m^{2} - s - k^{4})$

108 joules approx

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168 joules approx.

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182 joules approx.

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192 joules approx.

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Solution

The correct option is C
182 joules approx.

Rate of heat loss $E = ρ e A (T^{4} - T_{0}^{4})$
$= 5.6 \times 10^{- 8} \times 0.4 \times 200 \times 10^{- 4} \times [(273 + 527)^{4} - (273 + 27)^{4}]$
$= 5.67 \times 10^{- 8} \times 0.4 \times 200 \times 10^{- 4} \times (800)^{4} - (300)^{4} = 182 J / s e c$

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Similar questions

A metal ball of surface area $200 c m^{2}$ and temperature $527^{0} C$ is surrounded by a vessel at $27^{0} C .$ If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is $σ = 5.67 \times 10^{- 8} J / m^{2} - s - k^{4}$

Q. A metal ball of surface area

200 c m^{2}

and temperature

527^{\circ} C

is surrounded by a vessel at

27^{\circ} C

. If the emissivity of the metal is

0.4

, then the rate of loss of heat from the ball is

[σ = 5.67 \times 10^{- 8} J / m^{- 2} - s - k^{4}]

Q. A metal ball of surface area

200

c m^{2}

and temperature

527^{\circ} C

is surrounded by a vessel at

27^{\circ} C

. If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is approximately:

σ = 5.67 \times 10^{- 8} \frac{j o u l e}{m^{2} \times s e c \times K^{2}}

Q. A metallic sphere having radius 0.08 m and mass m = 10 kg is heated to a temperature of

227^{\circ}

C and suspended inside a box whose walls are at a temperature of

27^{\circ}

C. The maximum rate at which its temperature will fall is :
(Take e = 1, Stefan's constant; and specific heat of the metal s = 90 cal/kg/deg J = 4.2 Joules/Calorie)

Q. A heat engine receives

150

Joules of heat energy and performs

70

Joules of work. If heat loss in the surrounding is zero. Find out by what value does the internal energy of the system change?

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A metal ball of surface area 200 cm2 and temperature 527o C is surrounded by a vessel at 27o C. If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is (ρ=5.67×10−5J/m2−s−k4)

The correct option is C 182 joules approx. Rate of heat loss E=ρeA(T4−T40) =5.6×10−8×0.4×200×10−4×[(273+527)4−(273+27)4] =5.67×10−8×0.4×200×10−4×(800)4−(300)4=182 J/sec

A metal ball of surface area $200 c m^{2}$ and temperature $527^{o} C$ is surrounded by a vessel at $27^{o} C$ . If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is $(ρ = 5.67 \times 10^{- 5} J / m^{2} - s - k^{4})$