Question

A metal coin is at the bottom of a beaker filled with a liquid to a height of 6 cm. The R.I. of the liquid is 4/3. To an observer looking from above the surface of the liquid, the coin will appear raised up by

• A. 4.5 cm
• B. 6.75 cm
• C. 1.5 cm
• D. 7.5 cm

Answer 1

The correct option is C

1.5 cm

$\mu =\frac{\text{real depth}}{\text{apparent depth}}$ or $\frac{4}{3}=\frac{6}{x}$

$\therefore x=\frac{6\times 3}{4}=4.5cm$

So, required depth = 6 - 4.5 cm