Question

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is $0.2\times {10}^{-4}T$, then the e.m.f developed between the two ends of the conductor is

• A. 5 mV
• B. $50\mu V$
• C. $5\mu V$
• D. 50 mV

Answer 1

Answer: (B)

$50\mu V$

$I=2m,w=5rad/s,$

$B=0.2\times {10}^{-4}T$

$\epsilon =\frac{B\omega l}{2}$

$=\frac{0.2\times {10}^{-4}\times 5\times 1}{2}$

$=50\mu V$