Question

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is
$0.2\times {10}^{-4}T,$ then the e.m.f. developed between the two ends of the conductor is

• A. 5 mV
• B. $5\times {10}^{-4}$ V
• C. 50 mV
• D. 50$\mu$V

Answer 1

The correct option is D 50$\mu$V

$e=\frac{1}{2}Bw{r}^2=\frac{1}{2}\times 0.2\times {10}^{-4}\times 5\times (1{)}^2=50\mu V$