Question

A metal crystallises in a bcc structure with a cell edge length of 2.65A⁰. What is the radius of the atom?

Answer 1

Dear Student,

The computation for bcc structure are expressed below,

$$\begin{gathered} a=\frac{4R}{\sqrt{3}} \\ \Rightarrow R=\frac{\sqrt{3}a}{4}=\frac{\sqrt{3}\times 2.65\times {10}^{-10}}{4} \\ \Rightarrow R=1.147\times {10}^{-10} \\ R=1.147A^o \end{gathered}$$

Regards.