Question

A metal cube of length 10.0 mm at $0^{\circ }C$ (273K) is heated to ${200}^{\circ }C$ (473K). Given its coefficient of linear expansion is $2\times {10}^{-5}{K}^{-1}$. The percent change of its volume is

• A. 0.1
• B. 0.2
• C. 0.4
• D. 1.2

Answer 1

The correct option is D 1.2

Here percentage change in volume is given as, $\Delta V=\gamma \times t\times 100$
where, $\gamma =3\alpha$
So, $\Delta V=3\alpha \times (T_1-T_2)\times 100$
$\Delta V=3\times {2\times 10}^{-5}\times (473-273)\times 100=1.2$