A metal cube of side 1 cm at 10-C is heated- when its each side becomes 10 cm at 810-C- Calculate the value of superficial expansion

The correct option is A 0.0225^∘C L_0 = 1 cm L_1 = 10 cm t = (810 10) = 800^∘C α = L_t L_oL_o× t = 10 11× 800 = 9800 = 0.01125/ ...

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Byju's Answer

Standard XII

Physics

Area and Volume Expansion

A metal cube ...

Question

A metal cube of side $1 c m$ at $10^{\circ} C$ is heated, when its each side becomes $10 c m$ at $810^{\circ} C$ . Calculate the value of superficial expansion

{0.0225}^{\circ} C

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{0.01125}^{\circ} C

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{0.001}^{\circ} C

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{22.0}^{\circ} C

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Solution

The correct option is A ${0.0225}^{\circ} C$
$L_{0} = 1 c m L_{1} = 10 c m t = (810 - 10) = 800^{\circ} C$
$α = \frac{L_{t} - L_{o}}{L_{o} \times t} = \frac{10 - 1}{1 \times 800} = \frac{9}{800} = 0.01125 /^{\circ} C$
$β = 2 α = 0.0112 /^{\circ} C \times 2$
$= {0.0225}^{\circ} C$

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A metal cube of side 1 cm at 10∘C is heated, when its each side becomes 10 cm at 810∘C. Calculate the value of superficial expansion

The correct option is A 0.0225∘CL0=1 cmL1=10 cmt=(810−10)=800∘Cα=Lt−LoLo×t=10−11×800=9800=0.01125/∘Cβ=2α=0.0112/∘C×2=0.0225∘C

A metal cube of side $1 c m$ at $10^{\circ} C$ is heated, when its each side becomes $10 c m$ at $810^{\circ} C$ . Calculate the value of superficial expansion

The correct option is A ${0.0225}^{\circ} C$
$L_{0} = 1 c m L_{1} = 10 c m t = (810 - 10) = 800^{\circ} C$
$α = \frac{L_{t} - L_{o}}{L_{o} \times t} = \frac{10 - 1}{1 \times 800} = \frac{9}{800} = 0.01125 /^{\circ} C$
$β = 2 α = 0.0112 /^{\circ} C \times 2$
$= {0.0225}^{\circ} C$