Question

A metal cutting test was conducted on a lathe and the following were noted:
Vertical force on the tool = 2000 N
depth of cut = 2.00 mm
Feed = 5 cuts/mm
Pressure of the chip cross-sectional area on the tools is______ $kN/m{m}^2$

• A. 5

Answer 1

The correct option is A 5
Cross-sectional area of the chip = depth of cut $\times$feed per revolution

$=2.00\times \frac{1}{(No.ofcutspermm)}$

$=2\times \frac{1}{5}=0.4m{m}^2$

Pressure of chip cross-sectional area on the tool

$=\frac{2000}{0.4\times {10}^{-6}}=5000\times {10}^5$

$=5\times {10}^{9}N/m^2$

$=5kN/m{m}^2$