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Standard X

Physics

Watt Hour Meter

A metal drill...

Question

A metal drill of power 40 W, drills a hole in a lead cube of mass 1 kg in 8.5 seconds. The specific heat capacity of lead is 130 Jkg^–1°C^–1. If all the mechanical energy of the drill changes into heat energy, calculate the rise in temperature of lead cube.

0.62°C = θ

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0.38°C = θ

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2.62°F = θ

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2.62°C = θ

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Solution

The correct option is D
2.62°C = θ

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A steel drill making $180 r p m$ is used to drill a hole in a block of steel. The mass of the steel block and the drill is $180 g m$ . If the entire mechanical work is used up in producing heat and the rate of rise in temperature of the block and the drill is ${0.5}^{\circ} C / s$ .The torque required to drive the drill in Nm is

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A lead bullet penetrates into a solid object and melts. Assuming that 50% of its kinetic energy was used to heat it, calculate the initial speed of the bullet. The initial temperature of the bullet is $27^{\circ} C$ and its melting point is $327^{\circ} C$ . Latent heat of fusion of lead = $2.5 \times 10^{4} J k g^{- 1}$ and specific heat capacity of lead = $125 J k g^{1} K^{1}$ .

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A metal drill of power 40 W, drills a hole in a lead cube of mass 1 kg in 8.5 seconds. The specific heat capacity of lead is 130 Jkg–1°C–1. If all the mechanical energy of the drill changes into heat energy, calculate the rise in temperature of lead cube.

The correct option is D 2.62°C = θ

A metal drill of power 40 W, drills a hole in a lead cube of mass 1 kg in 8.5 seconds. The specific heat capacity of lead is 130 Jkg^–1°C^–1. If all the mechanical energy of the drill changes into heat energy, calculate the rise in temperature of lead cube.

The correct option is D
2.62°C = θ