A metal forms two oxides. The higher oxide contains 80% metal.0.72 g of the lower oxide gave 0.8g of the higher oxide when oxidize then the ratio of weight of oxygen that combines with fixed weight of metal in the two oxides will be (a) 2:3 (b)1:2 (c)4:5 (d)3:2

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Q. A metal forms two oxides. The higher oxide contains

80 %

metal.

0.72 g

of the lower oxide gave

0.8 g

of higher oxide when oxidized. Then the ratio of the weight of oxygen that combines with the fixed weight of the metal in the two oxides will be:

A metal forms two oxides, the higher oxide contains 80% metal, 0.72g of the lower oxide gave 0.8g of higher oxide on heating. Show that the data illustrates the law of multiple proportions?

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