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Standard XII

Chemistry

Reducing Nature (Group 2)

A metal gives...

Question

A metal gives two chlorides ‘A’ and ‘B’. ‘A’ gives black precipitate with $N H_{4} O H$ and ‘B’ gives white precipitate .With KI ,‘B’ gives a red precipitate soluble in excess of KI. ‘A’ and ‘B’ are respectively :

$H g C l_{2} a n d H g_{2} C l_{2}$

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$H g_{2} C l_{2} a n d H g C l_{2}$

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$H g C l_{2} a n d Z n C l_{2}$

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$Z n C l_{2} a n d H g C l_{2}$

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Solution

The correct option is B
$H g_{2} C l_{2} a n d H g C l_{2}$

Calomel on reaction with ammonium hydroxide turns black. The black substance is a mixture of mercury and mercuric amino chloride.

$H g_{2} C l_{2} + 2 N H_{4} O H ⟶ H g N H_{2} C l + H g + N H_{4} C l + 2 H_{2} O$

$H g C l_{2}$ forms white ppt of $H g_{2} C l_{2}$ .

$H g C l_{2} + 2 K I ⟶ H g I_{2} + 2 K C l$ .

$H g C l_{2} + 4 K I ⟶ K_{2} [H g I_{4}] + 2 K C l$ .

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Similar questions

A metal gives two chlorides ‘A’ and ‘B’. ‘A’ gives black precipitate with $N H_{4} O H$ and ‘B’ gives white. With KI ‘B’ gives a red precipitate soluble in excess of $K I$ . ‘A’ and ‘B’ are respectively :

Which of the following metal chloride gives white ppt and black ppt respectively with aequeous solution of gas (B)

Q. Salt (A) makes part of electrode and is insoluble in water. (A) is blackened by

{N H}_{3}

forming (B). (B) is soluble in aqua regia forming (C). (C) gives orange precipitate with KI but the precipitate dissolves in excess of KI forming (D). Here,
(A) :

{H g}_{2} {C l}_{2}

(calomel)
(B) :

({H g N H}_{2} C l + H g)

{H g C l}_{2}

(D) :

K_{2} {H g I}_{4}

If true enter 1, else enter 0.

A colourless mixture of two substances (A) and (B) (excess) is soluble in

H_{2} O

, separately. (A) turns blue litmus red and (B) turns red litmus blue. (A) gives white ppt. with (B), which dissolves in excess of (B) forming (C). (A) when placed in moist air gives fumes and can form a dimer. (A) gives white ppt. with

{N H}_{4} C l

and

{N H}_{4} O H

soluble in (B). (A) also gives white precipitate with

{A g N O}_{3}

soluble in

{N H}_{4} O H

Thus, colourless mixture contains ___________.

Q. Colourless solution of (A) gives white precipitate (B) with

A g N O_{3}

solution, soluble in aq.

N H_{3}

. (A) also gives white precipiatete (C) with NaOH soluble in excess of it forming (D). (D) gives white precipiate (E) with

H_{2} S

.(A), (B), (C), (D) and (E) are as follows.

(A) :

Z n C l_{2}

(B) :

A g C l

Z n (O H)_{2}

(D) :

N a_{2} Z n O_{2}

(E) :

Z n S

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A metal gives two chlorides ‘A’ and ‘B’. ‘A’ gives black precipitate with NH4OH and ‘B’ gives white precipitate .With KI ,‘B’ gives a red precipitate soluble in excess of KI. ‘A’ and ‘B’ are respectively :

The correct option is B Hg2Cl2 and HgCl2 Calomel on reaction with ammonium hydroxide turns black. The black substance is a mixture of mercury and mercuric amino chloride. Hg2Cl2+2NH4OH⟶HgNH2Cl+Hg+NH4Cl+2H2O HgCl2 forms white ppt of Hg2Cl2. HgCl2+2KI⟶HgI2+2KCl. HgCl2+4KI⟶K2[HgI4]+2KCl.

A metal gives two chlorides ‘A’ and ‘B’. ‘A’ gives black precipitate with $N H_{4} O H$ and ‘B’ gives white precipitate .With KI ,‘B’ gives a red precipitate soluble in excess of KI. ‘A’ and ‘B’ are respectively :