wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

A metal has a fcc lattice. The edge length of the cell is 404 pm. The density of the metal is 2.72 g cm3 . The molar mass of the metal is
(NA Avogadro's constant = 6.02×1023mol1)


A

27 g mol1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

20 g mol1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

40 g mol1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

30 g mol1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

27 g mol1


For fcc, Z=4

Note: We will convert all units to cm from m, this is an important step as density is given in g/cc. This will take care of the units of molar weight as well - g/mol.
d=ZMNAa3M=d×NA×a3Z=2.72×6.023×1023×(404×1010)34M=26.9927 g mol1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Density
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon