A metal hydrochloride of molecular formula $M (O H)_{2}$ is 50% dissociated in 0.0025M solution. The solution will have a pH:

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11.4

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Solution

The correct option is D 11.4
$M (O H)_{2} ⇋ M^{2 +} + 2 O H^{-}$
$c - c α$ $c α$ $2 c α$
$[O H^{-}] = 2 c α = 2 \times 0.0025 \times \frac{50}{100} = 2.5 \times 10^{- 3}$
$p O H = - log (2.5 \times 10^{- 3}) = 2.6$
$∴ p H = 14 - 2.6 = 11.4$

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