A metal ion $M^{3 +}$ loses three electrons. Its oxidation number will be:

+ 3

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+ 6

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0

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- 3

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Solution

The correct option is B $+ 6$
The reaction is as follows:

$M^{3 +} ⟶ M^{6 +} + 3 e^{-}$

So, the new oxidation of M is $+ 6$ .

Hence, the correct option is $B$

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$M^{+ 3}$ ion loses $3 e^{-}$ . Its oxidation number will be

+ 3

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