Given : T1=487oC=487+273=760K ; T2=2767oC=2767+273=3040K
Using Stefan's law; P=σAeT4
⟹P=PoT4 (where, Po=σAe)
by taking log at both side;
log2(P/Po)=4log2(T)
⟹ For T1,
1=4log2(760) ..........(1)
⟹ For T2,
Also, log2(P/Po)=4log2(3040) ......(2)
Equation (2) - (1), we get log2(P/Po)−1=4log23040760
where, (3040=4×760),
log2(P/Po)−1=4log2(4) or log2(P/Po)−1=8
⟹log2(P/Po)=9