A metal (M) is divalent in its 'ous' state and trivalent in its 'ic' state. Write the formula of metal phosphide.

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Solution

The formula of the metal phosphide in it's "ous" (+2) state can be written as follows:
$M^{+ 2} + P^{3 -} \to M_{3} P_{2}$

The formula of the metal phosphide in it's "ic" (+3) state can be written as follows:
$M^{+ 3} + P^{3 -} \to M P$

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A metal (M) is divalent in its 'ous' state and trivalent in its 'ic' state. Write the formula of metal phosphide.

The formula of the metal phosphide in it's "ous" (+2) state can be written as follows:M+2+P3−→M3P2The formula of the metal phosphide in it's "ic" (+3) state can be written as follows:M+3+P3−→MP

The formula of the metal phosphide in it's "ous" (+2) state can be written as follows:
$M^{+ 2} + P^{3 -} \to M_{3} P_{2}$

The formula of the metal phosphide in it's "ic" (+3) state can be written as follows:
$M^{+ 3} + P^{3 -} \to M P$