A metal 'M' is divalent in its 'ous' state and trivalent in its 'ic' state. Write the formula of Metal nitrate.

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Solution

For +2 (ous) oxidation state of metal, the reaction with nitrate is:

$M^{+ 2} + {N O}_{3}^{-} \to M {({N O}_{3})}_{2}$

For +3(ic) oxidation state of metal, the reaction with nitrate is:

$M^{+ 3} + {N O}_{3}^{-} \to M {({N O}_{3})}_{3}$

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A metal 'M' is divalent in its 'ous' state and trivalent in its 'ic' state. Write the formula of Metal nitrate.

For +2 (ous) oxidation state of metal, the reaction with nitrate is: M+2+NO−3→M(NO3)2For +3(ic) oxidation state of metal, the reaction with nitrate is: M+3+NO−3→M(NO3)3

For +2 (ous) oxidation state of metal, the reaction with nitrate is:

$M^{+ 2} + {N O}_{3}^{-} \to M {({N O}_{3})}_{2}$

For +3(ic) oxidation state of metal, the reaction with nitrate is:

$M^{+ 3} + {N O}_{3}^{-} \to M {({N O}_{3})}_{3}$