A metal $M$ of atomic mass 54.94 has a density of 7.42 g/cc. Calculate the apparent volume occupied by one atom of the metal.

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Solution

$A t o m i c m a s s = 54.94 d e n s i t y = 7.42 g / c c A p p a r e n t v o l u m e o c c u p i e d b y o n e a t o m = ? V o l u m e = \frac{m a s s}{d e n s i t y} = \frac{54.94}{7.42} = 7.40 {c m}^{3} (v o l u m e o f o n e m o l e)$
$v o l u m e o f o n e a t o m$ $= \frac{v o l u m e o f o n e m o l e}{6.022 \times 10^{- 23}} = \frac{7.40}{6.022 \times 10^{- 23}} = 1.23 \times 10^{- 23} {c m}^{3}$

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A metal M of atomic mass 54.94 has a density of 7.42 g/cc. Calculate the apparent volume occupied by one atom of the metal.

Atomicmass=54.94density=7.42g/ccApparentvolumeoccupiedbyoneatom=?Volume=massdensity=54.947.42=7.40cm3(volumeofonemole)volumeofoneatom =volumeofonemole6.022×10−23=7.406.022×10−23=1.23×10−23cm3

A metal $M$ of atomic mass 54.94 has a density of 7.42 g/cc. Calculate the apparent volume occupied by one atom of the metal.