Question

A metal M of atomic weight $54.94$ g has a density of $7.42$ g/cc. The apparent volume occupied by one atom of the metal will be:

• A. $8.13\times {10}^{-23}cc$
• B. $1.83\times {10}^{23}cc$
• C. $1.23\times {10}^{-23}cc$
• D. $7.404cc$

Answer 1

Answer: (C)

$1.23\times {10}^{-23}cc$

$1$ mole ($54.94$ g) of metal M contains $6.02\times {10}^{23}$ atoms.

Weight of one atom $=\frac{54.94}{6.02\times {10}^{23}}=9.12\times {10}^{-23}$ g

Volume occupied by 1 atom $=\frac{mass}{density}=\frac{9.12\times {10}^{-23}}{7.42}=1.23\times {10}^{-23}$ cc.

Hence, option C is correct.