Question

A metal M of equivalent mass E forms an oxide of molecular formula $M_x{O}_v$. The atomic mass of the metal is given by the correct equation.

• A. 2E(y/x)
• B. xyE
• C. E/y
• D. y/E
• E. E/2 (x/y)

Answer 1

The correct option is A 2E(y/x)

$M_x{O}_y$

Valence of oxygen is $-2$

Valance of y of oxygen is $-2y$

Let valence of $M$ is $+P$

Charge on x molecule of M is $+Px$

Compound is neutral

$-2y+Px=0$

$\Rightarrow P=\frac{2y}{x}electron$

Valence of metal M Is $\frac{2y}{x}$, atomic mass of M is $\frac{2y}{x}E$

Hence, atomic mass of M is $\frac{2yE}{x}$.