A metal 'M' on oxidation gives metal oxides MO that contains 80% oxygen. Calculate the atomic weight of metal.

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Solution

In $100$ $g$ $M O ⟶ 80$ $g m$ $O$ atom and $20$ $g$ metal is present.
Moles of $O$ atoms $= \frac{80}{16} = 5$ $m o l e s$
$1 : 1$ composition
Let $W$ be atomic weight of metal.
$\frac{20}{W} = 5$
$⟹ W = 4$

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A metal 'M' on oxidation gives metal oxides MO that contains 80% oxygen. Calculate the atomic weight of metal.

In 100 g MO⟶80 gm O atom and 20 g metal is present.Moles of O atoms =8016=5 moles 1:1 compositionLet W be atomic weight of metal.20W=5⟹W=4

In $100$ $g$ $M O ⟶ 80$ $g m$ $O$ atom and $20$ $g$ metal is present.
Moles of $O$ atoms $= \frac{80}{16} = 5$ $m o l e s$
$1 : 1$ composition
Let $W$ be atomic weight of metal.
$\frac{20}{W} = 5$
$⟹ W = 4$