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Diagonal Relationship between Li and Mg

A metal M rea...

Question

A metal $M$ readily forms water soluble $M S O_{4} .$ It also forms oxide $M O$ which becomes inert on heating. Hydroxide $M (O H)_{2}$ is insoluble in water but soluble in $N a O H$ solution. What is $M$ ?

M g

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B a

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C a

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B e

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Solution

The correct option is D $B e$
$B e S O_{4}$ is solube in water. $B e O$ becomes inert on heating. $B e (O H)_{2}$ is insoluble and reacts with $N a O H .$ The product is soluble in water.
$B e (O H)_{2} + 2 N a O H \to N a_{2} B e O_{2} S o l u b l e + 2 H_{2} O$

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Similar questions

Q. A metal M readily forms water soluble

M S O_{4}

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M (O H)_{2}

is insoluble in water but soluble in NaOH solution. What is M?

Q. A metal

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readily forms sulphate

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which is water soluble. It forms oxide

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readily forms water soluble sulphate

M S O_{4}

, water insoluble hydroxide

M (O H)_{2}

and oxide

M O

which becomes inert on heating. The hydroxide is soluble in

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. The

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readily forms water soluble sulphate

M S O_{4}

, water insoluble hydroxide

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A metal M readily forms water soluble MSO4. It also forms oxide MO which becomes inert on heating. Hydroxide M(OH)2 is insoluble in water but soluble in NaOH solution. What is M ?

The correct option is D BeBeSO4 is solube in water. BeO becomes inert on heating. Be(OH)2 is insoluble and reacts with NaOH. The product is soluble in water. Be(OH)2+2NaOH→Na2BeO2Soluble+2H2O

A metal $M$ readily forms water soluble $M S O_{4} .$ It also forms oxide $M O$ which becomes inert on heating. Hydroxide $M (O H)_{2}$ is insoluble in water but soluble in $N a O H$ solution. What is $M$ ?

The correct option is D $B e$
$B e S O_{4}$ is solube in water. $B e O$ becomes inert on heating. $B e (O H)_{2}$ is insoluble and reacts with $N a O H .$ The product is soluble in water.
$B e (O H)_{2} + 2 N a O H \to N a_{2} B e O_{2} S o l u b l e + 2 H_{2} O$