A metal nitrate reacts with $K I$ to give a black precipitate which on addition of excess of $K I$ converts to an orange color solution. The cation of metal nitrate is :

H g^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B i^{3 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P b^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C u^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $B i^{3 +}$
Option (B) is correct.
The cation of metal nitrate is $B i^{3 +}$ .
$\begin{matrix} B i^{3 +} & + & 3 K I & ⟶ & B i I_{3} ↓ & + 3 K^{+} B l a c k \end{matrix}$

$\begin{matrix} B i I_{3} & + & K I & ⟶ & K [B i I_{4}] O r a n g e s o l u t i o n \end{matrix}$

Suggest Corrections

Similar questions

Q. To a metal nitrate, when

K I

solution is added, a black precipitate is produced at first; on adding excess of

K I

, orange solution is produced. Identify the metal ion.

To a metal nitrate, when KI solution is added, a black ppt. is produced at first, on adding excess of KI orange solution is produced. Metal chloride gives white turbidity on dilution. Metal belongs to nth A group and mth period of periodic table. Then value of m + n is