A metal oxide that is reduced by hydrogen is:

A l_{2} O_{3}

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C u O

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C a O

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N a_{2} O

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Solution

The correct option is B $C u O$
Reduction of copper oxide with hydrogen:
$C u O + H_{2} \to C u + H_{2} O 2 C u + O_{2} \to 2 C u O$
Al, Ca, Na are present higher in the reactivity series, so their oxides are not reduced by hydrogen. While copper comes below hydrogen in the activity series, so its oxide is reduced by hydrogen.

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