A metal pipe has a bore (inner diameter) of 5 cm. The pipe is 5 mm thick all round. Find the weight, in the kilogram, of 2 meters of the pipe if 1 $c m^{3}$ of the metal weighs 7.7 g.

12.31 kg

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19.31 kg

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13.31 kg

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14.31 kg

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Solution

The correct option is B 13.31 kg
Inner diameter=5 cm. radius=2.5cm
thickness =5mm=0.5cm
outer radius=2.5+0.5=3cm
length=2m=200cm
volume of pipe=
$V = Π {(R}^{2} - r^{2}) h$
$V = 3.14 {(3}^{2} - {2.5}^{2}) * 200$
$V = 22 / 7 * (9 - 6.25) * 200$
$V = 12100 / 7 {c m}^{3}$
1 $c m^{3}$ of the metal weighs 7.7 $g$ .
$S o, \frac{12100}{7} c m^{3} w e i g h s = 7.7 * \frac{12100}{7} g m = 13310 g m = 13.31 k g$

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A metal pipe has a bore (inner diameter) of 5 cm. The pipe is 5 mm thick all round. Find the weight, in the kilogram, of 2 meters of the pipe if 1 cm3 of the metal weighs 7.7 g.

The correct option is B 13.31 kgInner diameter=5 cm. radius=2.5cmthickness =5mm=0.5cmouter radius=2.5+0.5=3cmlength=2m=200cmvolume of pipe=V=Π(R2−r2)hV=3.14(32−2.52)∗200V=22/7∗(9−6.25)∗200V=12100/7cm3 1 cm3 of the metal weighs 7.7 g.So,121007cm3weighs=7.7∗121007gm=13310gm=13.31kg

A metal pipe has a bore (inner diameter) of 5 cm. The pipe is 5 mm thick all round. Find the weight, in the kilogram, of 2 meters of the pipe if 1 $c m^{3}$ of the metal weighs 7.7 g.