A metal pipe is 77cm long the inner diameter of a cross section is 4cm,the outer diameter is 4.4cm find its total surface area

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Solution

H=77cm
r₁=4.4cm
r₂=4cm

now find l²=h²+(r₁-r₂)²=5929+0.16=5929.16
so, l=70

now all we have to do is to use this:
" πl(r₁+r₂)+π(r₁)²+π(r₂)² "

=[3.1470(8.4)]+[3.1419.36]+[3.1416]

=1848+60.85+50.29

=1959.14

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A metal pipe is 77cm long the inner diameter of a cross section is 4cm,the outer diameter is 4.4cm find its total surface area

H=77cm r₁=4.4cm r₂=4cm now find l²=h²+(r₁-r₂)²=5929+0.16=5929.16 so, l=70 now all we have to do is to use this: " πl(r₁+r₂)+π(r₁)²+π(r₂)² " =[3.14*70*(8.4)]+[3.14*19.36]+[3.14*16] =1848+60.85+50.29 =1959.14

H=77cm
r₁=4.4cm
r₂=4cm

now find l²=h²+(r₁-r₂)²=5929+0.16=5929.16
so, l=70

now all we have to do is to use this:
" πl(r₁+r₂)+π(r₁)²+π(r₂)² "

=[3.1470(8.4)]+[3.1419.36]+[3.1416]

=1848+60.85+50.29

=1959.14