A metal plate of mass 250gm is balanced in air by throwing balls each of mass 25gm vertically up. if the ball rebound at the rate of 20 per second with the same velocity, the velocity with which the balls strike the plate is (g=10ms−2)
Given that,
Mass of metal plate = 0.25 kg
Mass of each ball = 0.025 kg
Number of balls = 20
Now, the plate is balanced so the force exerted by plate is equal to the force of 20 balls
mg=20×mvt
0.25×10=20×0.025×v1
v=0.25×1020×0.025
v=5m/s
Hence the velocity with which the balls strike the plate is 5 m/s.