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Diagonal Relationship between Li and Mg

A metal readi...

Question

A metal readily forms its sulphate $M S O_{4}$ which is water soluble. It forms its oxide MO which becomes inert on heating. It forms its insoluble hydroxide $M (O H)_{2}$ which is soluble in NaOH solution. What would be M?

A

Be

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B

Ba

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C

Ca

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D

Mg

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Solution

The correct option is A Be
Metal Be forms water soluble $B e S O_{4}$ and forms $B e O$ which on heating turns inert. $B e$ forms an insoluble hydroxide $B e (O H)_{2}$ which is soluble in $N a O H$ giving sodium berylate $N a_{2} B e O_{2}$

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Similar questions

M

readily forms its sulphate

M S O_{4}

which is water soluble. It forms its oxide

M O

which becomes inert on heating. It forms an insoluble hydroxide

M (O H)_{2}

which is soluble in

N a O H

solution. Then M is:

Q. A metal M readily forms water soluble

M S O_{4}

. It also forms oxide MO which becomes inert on heating. Hydroxide

M (O H)_{2}

is insoluble in water but soluble in NaOH solution. What is M?

M

readily forms sulphate

M S O_{4}

which is water soluble. It forms oxide

M O

which becomes inert on heating. It forms insoluble hydroxide which is soluble in

N a O H

M

M

readily forms water soluble

M S O_{4} .

It also forms oxide

M O

which becomes inert on heating. Hydroxide

M (O H)_{2}

is insoluble in water but soluble in

N a O H

solution. What is

M

Q. A metal M readily forms water-soluble sulphate

M S O_{4}

, water insoluble hydroxide

M (O H)_{2}

and oxide MO which becomes inert on heating.

The hydroxide is soluble in NaOH. The metal M is:

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