A metal rod at a temperature of $150^{\circ} C$ radiates energy at a rate of 20 W. If its temperature is increased to $300^{\circ} C$ , find the rate of energy radiation.

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Solution

From Stefan's law, $\frac{E_{2}}{E_{1}} = \frac{σ A {T_{2}}^{4}}{σ A {T_{1}}^{4}} \Rightarrow \frac{E_{2}}{20} = \frac{{T_{2}}^{4}}{{T_{1}}^{4}} = \frac{(300 + 273)^{4}}{(150 + 273)^{4}} ∴ E_{2} = 67.3 W$

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A metal rod at a temperature of 150∘C radiates energy at a rate of 20 W. If its temperature is increased to 300∘C, find the rate of energy radiation.

From Stefan's law, E2E1=σAT24σAT14⇒E220=T24T14=(300+273)4(150+273)4∴E2=67.3 W

A metal rod at a temperature of $150^{\circ} C$ radiates energy at a rate of 20 W. If its temperature is increased to $300^{\circ} C$ , find the rate of energy radiation.

From Stefan's law, $\frac{E_{2}}{E_{1}} = \frac{σ A {T_{2}}^{4}}{σ A {T_{1}}^{4}} \Rightarrow \frac{E_{2}}{20} = \frac{{T_{2}}^{4}}{{T_{1}}^{4}} = \frac{(300 + 273)^{4}}{(150 + 273)^{4}} ∴ E_{2} = 67.3 W$