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Question

A metal rod has a length of 1m at 30oC. α of metal is 2.5×105/oC. The temperature at which it will be shortened by 1mm is:

A
30o
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B
40o
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C
10o
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D
10o
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Solution

The correct option is C 10o
l=1mT=30°Cαmetal=2.5×105°CΔl=1mmlf=li(1+αΔT)lflili=αΔT1mm1mm=αΔTΔT=2.5×105×11×103ΔT=1×1031×2.5×105=(1002.5)=40TfTi=40Tf=Ti40=3040=10°C

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