wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A metal rod of uniform thickness and of length 1m is suspended at its 25cm division with the help of a string. The rod remains horizontally straight when a block of mass 2kg is suspended to the rod at its 10cm division from same end. The mass of the rod is:

A
0.4 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.8 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.2 kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.6 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.2 kg
Torques balance each other
mg(25)=2g(15)
15cm is a distance of the suspended mass from point of suspension
25m=30
m=3025=1.2kg

64335_19594_ans_df420a8402434dc2b2c01d372a9e2c69.png

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cel & Mia at Wonderla
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon