A metal sheet of thickness 2 cm was used to make a container of external dimensions 30 cm - 15 cm - 25 cm- which is open from the top- Find the volume of metal used-A- 6578 cm 3B- 11250 cm 3C- 12250 cm 3D- 4672 cm 3

The correct option is D 4672 cm^3 External volume of tank = 30cm × 15cm × 25cm = 11250cm^3 Internal measurement = 26cm × 11cm × 23cm Hence inner volume = ...

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Standard VIII

Mathematics

Volume of a Cuboid

A metal sheet...

Question

A metal sheet of thickness 2cm was used to make a container of external dimensions $30 c m \times 15 c m \times 25 c m$ , which is open from the top. Find the volume of metal used.

$6578 c m^{3}$

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$11250 c m^{3}$

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$12250 c m^{3}$

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$4672 c m^{3}$

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Solution

The correct option is D
$4672 c m^{3}$

External volume of tank = $30 c m \times 15 c m \times 25 c m$ = $11250 c m^{3}$

Internal measurement = $26 c m \times 11 c m \times 23 c m$

Hence inner volume = $26 c m \times 11 c m \times 23$ = $6578 c m^{3}$

Hence, the volume of metal used = $11250 c m^{3} - 6578 c m^{3}$ = $4672 c m^{3}$

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A metal sheet of thickness 2cm was used to make a container of external dimensions 30cm×15cm×25cm, which is open from the top. Find the volume of metal used.

The correct option is D 4672 cm3 External volume of tank = 30cm×15cm×25cm = 11250cm3 Internal measurement = 26cm×11cm×23cm Hence inner volume = 26cm×11cm×23 = 6578cm3 Hence, the volume of metal used = 11250cm3 − 6578cm3 = 4672cm3

A metal sheet of thickness 2cm was used to make a container of external dimensions $30 c m \times 15 c m \times 25 c m$ , which is open from the top. Find the volume of metal used.