A metal sphere connected by a string is dipped in a liquid of density - as shown in the figure- The pressure at the bottom of the vessel will be p 0- atmospheric pressureA- p p 0- g hD- po

The correct option is B p = p_0 + ρ ghUpthrust on sphere from the liquid makes equal and opposite pair of forces. Hence there will be no effect on the pressure ...

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Standard VIII

Chemistry

Surface Tension

A metal spher...

Question

A metal sphere connected by a string is dipped in a liquid of density $ρ$ as shown in the figure. The pressure at the bottom of the vessel will be ( $p_{0}$ = atmospheric pressure)

p = p_{0} + ρ g h

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p > p_{0} + ρ g h

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p < p_{0} + ρ g h

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p_{0}

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Solution

The correct option is A $p = p_{0} + ρ g h$
The weight of the sphere (mg) gets balanced by the upthrust on the sphere from the liquid which makes an equal and opposite pair of forces. Hence there will be no effect on the pressure at bottom of vessel. Or $p = p_{0} + ρ g h$

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A metal sphere connected by a string is dipped in a liquid of density ρ as shown in the figure. The pressure at the bottom of the vessel will be (p0 = atmospheric pressure)

The correct option is A p=p0+ρghThe weight of the sphere (mg) gets balanced by the upthrust on the sphere from the liquid which makes an equal and opposite pair of forces. Hence there will be no effect on the pressure at bottom of vessel. Or p=p0+ρgh

A metal sphere connected by a string is dipped in a liquid of density $ρ$ as shown in the figure. The pressure at the bottom of the vessel will be ( $p_{0}$ = atmospheric pressure)

The correct option is A $p = p_{0} + ρ g h$
The weight of the sphere (mg) gets balanced by the upthrust on the sphere from the liquid which makes an equal and opposite pair of forces. Hence there will be no effect on the pressure at bottom of vessel. Or $p = p_{0} + ρ g h$