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Question
A metal sphere is heated from 0∘C to 100∘C. The change in volume of 10 cm radius is
(γ=6.3×10−5/∘C)
A metal sphere is heated from 0∘C to 100∘C. The change in volume of 10 cm radius is
(γ=6.3×10−5/∘C)
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Solution
The correct option is C 26.4cc
In this case, t=100∘ C; r1=10 cm; r2=?;γ=6.3×10−5/∘C or α=2.1×10−5/∘C
r2=r1(1+αt)
Putting all the values of r1,α,t, we get, r2 =10.021 cm
Now, v2−v1=(4/3)π(r32−r31)
Putting values of r1 and r2, we get,
Change in volume = 26.4cc
In this case, t=100∘ C; r1=10 cm; r2=?;γ=6.3×10−5/∘C or α=2.1×10−5/∘C
r2=r1(1+αt)
Putting all the values of r1,α,t, we get, r2 =10.021 cm
Now, v2−v1=(4/3)π(r32−r31)
Putting values of r1 and r2, we get,
Change in volume = 26.4cc
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