wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A metal wire is stretched by a load. Then the fractional change in its volume ΔVV is proportional to

A
ΔLL
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(ΔL2)2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ΔLL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(ΔLL)3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A ΔLL
From the data given in the question, a load F acting on the metallic wire is as shown in figure.


It is given that, the wire will stretch.
The length of wire will increase
We know, Poisson's ratio, e=ΔddΔLL(1)
Volume of wire, V=A×L=πd2L4 where d is the diameter of the wire.
ΔV=πd24ΔL+πL4×2dΔd
ΔVV=ΔLL+2Δdd
ΔVV=(12e)ΔLL
[using (1)]
Therefore, ΔVVΔLL

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon