Question

A metal $X$ on heating in nitrogen gas gives $Y$. $Y$ on treatment with $H_{2}O$ gives a colourless gas which when passed through $CuS{O}_4$ solution gives a blue colour. $Y$ is:

• A. $Mg(N{O}_3{)}_2$
• B. $M{g}_3{N}_2$
• C. $N{H}_3$
• D. $MgO$

Answer 1

The correct option is B $M{g}_3{N}_2$

Reaction:
$3Mg+N_2\to M{g}_3{N}_2$

$M{g}_3{N}_2+6H_{2}O\to 3Mg(OH{)}_2+2N{H}_3$