A metal X on heating in nitrogen gas gives Y. Y on treatment with $H_{2} O$ gives a colourless gas which when passed through $C u S O_{4}$ solution gives a blue colour. Y is

M g (N O_{3})_{2}

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M g_{3} N_{2}

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N H_{3}

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M g O

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Solution

The correct option is B $M g_{3} N_{2}$
$3 M g + N_{2} \to M g_{3} N_{2}$
$M g_{3} N_{2} + H_{2} O \to M g (O H)_{2} + N H_{3}$
$C u S O_{4} + 4 N H_{3} \to \begin{matrix} C u [(N H_{3})_{4})] S O_{4} deep blue colour \end{matrix}$
Magnesium (X) on heating in nitrogen gas gives magnesium nitride. Magnesium nitride (Y) on treatment with $H_{2} O$ gives a colourless gas ammonia which when passed through $C u S O_{4}$ solution gives a blue colour. Thus Y is magnesium nitride.

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