An iron bar of length 10 m is heated from $0^{0} C to 100^{0} C$ . If the coefficient of linear thermal expansion of iron is $10 \times 1 0^{- 6} /^{0} C$ the increases in the length of the bar is

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A metallic bar is heated from 0∘C to 100∘C; The coefficient of linear expansion is 10−5K−1. What will be the percentage increase in length?

The correct option is B 0.1%We know that thermal expansion is given as Δll=α(ΔT)Δll=10−5×(100−0)=10−3So for percentage change:Δll×100=10−5×(100−0)=10−3×100=0.1

A metallic bar is heated from $0^{\circ}$ C to $100^{\circ}$ C; The coefficient of linear expansion is $10^{- 5} K^{- 1}$ . What will be the percentage increase in length?

The correct option is B 0.1%
We know that thermal expansion is given as $\frac{Δ l}{l} = α (Δ T)$
$\frac{Δ l}{l} = 10^{- 5} \times (100 - 0) = 10^{- 3}$
So for percentage change:
$\frac{Δ l}{l} \times 100 = 10^{- 5} \times (100 - 0) = 10^{- 3} \times 100 = 0.1$