A metallic block of density 5 gm cm -3 and having dimensions 5 cm - 5 cm - 5 cm is weighed in water- Its apparent weight will beA- 4 - 4 - 4 - 4 gfB- 5 - 5 - 5 - 5 g fC- 5 - 4 - 4 - 4 gfD- 4 - 5 - 5 - 5 gf

The correct option is D 4 × 5 × 5 × 5 gf Apparent weight =V(ρ σ)g =l× b× h× (5 1)× g =(5× 5× 5× 4× g) dyne = (4× 5× 5× 5) gf ...

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Standard XII

Physics

Buoyant Force

A metallic bl...

Question

A metallic block of density 5 gm $c m^{- 3}$ and having dimensions 5 cm $\times$ 5 cm $\times$ 5 cm is weighed in water. Its apparent weight will be

5 × 5 × 5 × 5 gf

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4 × 4 × 4 × 4 gf

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5 × 4 × 4 × 4 gf

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4 × 5 × 5 × 5 gf

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Solution

The correct option is D
4 × 5 × 5 × 5 gf

Apparent weight

$= V (ρ - σ) g = l \times b \times h \times (5 - 1) \times g$

$= (5 \times 5 \times 5 \times 4 \times g)$ dyne = $(4 \times 5 \times 5 \times 5) g f$

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A metallic block of density 5 gm cm−3 and having dimensions 5 cm × 5 cm × 5 cm is weighed in water. Its apparent weight will be

The correct option is D 4 × 5 × 5 × 5 gf Apparent weight =V(ρ−σ)g=l×b×h×(5−1)×g =(5×5×5×4×g) dyne = (4×5×5×5) gf

A metallic block of density 5 gm $c m^{- 3}$ and having dimensions 5 cm $\times$ 5 cm $\times$ 5 cm is weighed in water. Its apparent weight will be

The correct option is D
4 × 5 × 5 × 5 gf

Apparent weight

$= V (ρ - σ) g = l \times b \times h \times (5 - 1) \times g$

$= (5 \times 5 \times 5 \times 4 \times g)$ dyne = $(4 \times 5 \times 5 \times 5) g f$