Question

A metallic bucket, open at the top, of height $24cm$ is in the form of the frustum of a cone, the radii of whose lower and upper circular ends are $7cm$ and $14cm$ respectively. Find:
(i) the volume of water which can completely fill the bucket.
(ii) the area of metal sheet used to make the bucket. [Use $\pi =\frac{22}{7}$]

• A. $8622$
• B. $8624$
• C. $8660$
• D. $8824$

Answer 1

The correct option is B $8624$

Volume of water$=$Volume of frustum of cone

Given $h=24$cm

$R=14$cm

$r=17$cm

Volume of frustum of cone

$=\frac{\pi h}{3}(R^2+Rr+r^2)$

$=\frac{22\times 24}{7\times 3}\left(\right(14{)}^2+14\times 7+\left(7{)}^2\right)$

$=\frac{22\times 24}{7\times 3}[196+98+49]$

$=\frac{22\times 8}{7}\left[343\right]$

$=22\times 8\times 49$

$=8624c{m}^3$.