A metallic element has a cubic lattice- Each edge of the unit cell is 2 A - The density of the metal is 2-5 g - cm 3- The unit cells in 200 g of metal areA- 1022B- 1024C- 1020D- 1025

The correct option is D 10^25V=a^3=8 × 10^ 24c.c Mass of 1 unit cell = v × d = 8 × 10^ 24 × 2.5 Number of unit cells in 200 g of metal =200/8 × 10^ 24× 2.5=10 ...

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Standard XII

Chemistry

Coordination Number

A metallic el...

Question

A metallic element has a cubic lattice. Each edge of the unit cell is $2 A^{\circ}$ . The density of the metal is 2.5g/ $c m^{3}$ . The unit cells in 200 g of metal are

10^{24}

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10^{20}

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10^{22}

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10^{25}

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Solution

The correct option is D $10^{25}$
$V = a^{3} = 8 \times 10^{- 24} c . c$
Mass of 1 unit cell = v $\times$ d = 8 $\times$ $10^{- 24}$ $\times$ 2.5
Number of unit cells in 200 g of metal
$= \frac{200}{8 \times 10^{- 24} \times 2.5} = 10^{25}$

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A metallic element has a cubic lattice. Each edge of the unit cell is 2A∘. The density of the metal is 2.5g/cm3. The unit cells in 200 g of metal are

The correct option is D 1025V=a3=8×10−24c.c Mass of 1 unit cell = v × d = 8 × 10−24 × 2.5 Number of unit cells in 200 g of metal =2008×10−24×2.5=1025

A metallic element has a cubic lattice. Each edge of the unit cell is $2 A^{\circ}$ . The density of the metal is 2.5g/ $c m^{3}$ . The unit cells in 200 g of metal are

The correct option is D $10^{25}$
$V = a^{3} = 8 \times 10^{- 24} c . c$
Mass of 1 unit cell = v $\times$ d = 8 $\times$ $10^{- 24}$ $\times$ 2.5
Number of unit cells in 200 g of metal
$= \frac{200}{8 \times 10^{- 24} \times 2.5} = 10^{25}$