A metallic ring with a small cut is held horizontally and a magnet is allowed to fall vertically through the ring then the acceleration of the magnet is

always equal to

g

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initially less than

g

but greater than

g

once it passes through the ring

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initially less than

g

but less than

g

once it passes through the ring

No worries! We‘ve got your back. Try BYJU‘S free classes today!

always less than

g

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Solution

The correct option is A always equal to $g$
As the ring has a cut in it so it will get induced emf when flux change due to motion of the magnet but there will $n o t$ be any $i n d u c e d$ current because circuit is $i n c o m p l e t e$ due to cut, so there will be no extra field due ring so no effect on motion of magnet so its acceleration will be constant as $g$ .

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