A metallic rod of length L and mass M is moving under the action of two unequal forces F1 and F2 (directed opposite to each other) acting at its ends along its length. Ignore gravity and any external magnetic field. If specific charge of electrons is (e/m), then the potential difference between the ends of the rod is steady state must be:
For the entire rod, assuming an acceleration a
F1−F2=M×a−−−−−(1)
For the same rod (therefore same acceleration)
Consider only length x
F1−T=(M×xL)a.
Plugging in a=(F1−F2M) from equation 1,
F1−T=(M×xL)×(F1−F2M)
T=F1−(F1−F2)×xL
Hence, The Option D is correct None