A metallic sphere floats in an immiscible mixture of water (density 103 kg/m3) and a liquid (density 8×103kg/m3) such that its (23) part is in water and (13) part in the liquid. The density of the metal is
Obviously water will float on top of the liquid. If the total volume of the ball is V from free body diagram
mg=FB+FBq
let density of water be ρω, density of liquid be ρl and density of ball be ρ.
ρ Vg=ρl13V g+ρω23V g
ρ=13ρl+23ρω
=13(8000)+23(1000)
=100003