A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

In AD, but not in BC

No worries! We‘ve got your back. Try BYJU‘S free classes today!

In BC, but not in AD

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Neither in AD nor in BC

No worries! We‘ve got your back. Try BYJU‘S free classes today!

In both AD and BC

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D In both AD and BC
Both AD and BC are straight conductors moving in a uniform magnetic field and emf will be induced in both. This will cause electric fields in both, but no net current flows in the circuit.

Suggest Corrections

Similar questions

Q. A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

Q. A metallic square loop

A B C D

is moving in its own plane with velocity

\to V

in a uniform magnetic field perpendicular to its plane as shown in fig. Then, an electric field induced

Metallic square loop ABCD is moving in its own plane with velocity V in a uniform magnetic field perpendicular to its plane as shown in the fig. An electric field is induced

Q. A metallic square loop

A B C D

is moving in its own plane with velocity

\to V

in a uniform magnetic field perpendicular to its plane as shown in fig. Then, an electric field induced

A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in Fig. 25.25. An electric field is induced

Join BYJU'S Learning Program

A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

The correct option is D In both AD and BCBoth AD and BC are straight conductors moving in a uniform magnetic field and emf will be induced in both. This will cause electric fields in both, but no net current flows in the circuit.

The correct option is D In both AD and BC
Both AD and BC are straight conductors moving in a uniform magnetic field and emf will be induced in both. This will cause electric fields in both, but no net current flows in the circuit.