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Standard X

Physics

Magnetic Field Due to a Straight Current Carrying Conductor

A metallic sq...

Question

A metallic square loop is moving in its own plane with velocity $v$ in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

in AD, but not in BC

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in BC, but not in AD

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neither AD nor BC

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in both AD and BC

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Solution

The correct option is D in both AD and BC
Both AD and BC are straight conductors moving in a uniform magnetic field and emf will be induced in both. This will cause electric field in both.

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A metallic square loop is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

The correct option is D in both AD and BCBoth AD and BC are straight conductors moving in a uniform magnetic field and emf will be induced in both. This will cause electric field in both.

A metallic square loop is moving in its own plane with velocity $v$ in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

The correct option is D in both AD and BC
Both AD and BC are straight conductors moving in a uniform magnetic field and emf will be induced in both. This will cause electric field in both.