A metallic surface when illuminated with light of wavelength $3333 ˚ A$ emits electrons with energies upto $0.6 e V$ . Calculate the work function of the metal.

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Solution

Work function of the metal $= W = \frac{h c}{λ} -$ K.E
$= [\frac{6.626 \times 10^{- 34} \times 3 \times 10^{8}}{3333 \times 10^{- 10}}] - [0.6 \times 1.6 \times 10^{- 19}]$
$= 5.96 \times 10^{- 19} - 0.96 \times 10^{- 19}$
$= 5 \times 10^{- 19} J$
$W = \frac{5 \times 10^{- 19}}{1.6 \times 10^{- 19}} e V$
$W = 3.125 e V$

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A metallic surface when illuminated with light of wavelength 3333˚A emits electrons with energies upto 0.6eV. Calculate the work function of the metal.

Work function of the metal =W=hcλ−K.E =[6.626×10−34×3×1083333×10−10]−[0.6×1.6×10−19] =5.96×10−19−0.96×10−19 =5×10−19JW=5×10−191.6×10−19eVW=3.125eV

A metallic surface when illuminated with light of wavelength $3333 ˚ A$ emits electrons with energies upto $0.6 e V$ . Calculate the work function of the metal.