A metallic washer of internal diameter $5 c m$ is heated by $500^{\circ} C$ . If the coefficient of linear expansion of metal is $1.8 \times 10^{- 5}$ per $^{\circ} C$ , then the final diameter will be 5.045

4.945 cm

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Solution

The correct option is A
4.945 cm

Given, $L_{0} = 5 c m, α = 1.8 \times 10^{- 5}$ per $^{\circ} C$ , $t = 500^{\circ} C$

Final diameter $L_{t} = L_{0} (1 + α \times t)$

= $5 \times [1 + (1.8 \times 10^{- 5}) \times 500]$

= $5.045 c m$

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A metallic washer of internal diameter 5 cm is heated by 500 ∘C. If the coefficient of linear expansion of metal is 1.8 × 10−5 per ∘C, then the final diameter will be 5.045

The correct option is A 4.945 cm Given, L0=5cm,α=1.8 × 10−5 per ∘C, t = 500 ∘C Final diameter Lt = L0 (1 + α × t) = 5 × [1 + (1.8 × 10−5) × 500] = 5.045 cm

A metallic washer of internal diameter $5 c m$ is heated by $500^{\circ} C$ . If the coefficient of linear expansion of metal is $1.8 \times 10^{- 5}$ per $^{\circ} C$ , then the final diameter will be 5.045

The correct option is A
4.945 cm

Given, $L_{0} = 5 c m, α = 1.8 \times 10^{- 5}$ per $^{\circ} C$ , $t = 500^{\circ} C$

Final diameter $L_{t} = L_{0} (1 + α \times t)$

= $5 \times [1 + (1.8 \times 10^{- 5}) \times 500]$

= $5.045 c m$