A metallic wire of density $ρ$ floats horizontal in water. The maximum radius of the wire so that the wire may not sink will be (Surface tension of water = T and angle of contact $θ = 0^{\circ}) .$

\sqrt{\frac{2 T}{π ρ g}}

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\sqrt{\frac{4 T}{ρ g}}

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\sqrt{\frac{T}{π ρ g}}

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\sqrt{\frac{T ρ}{π g}}

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Solution

The correct option is A
$\sqrt{\frac{2 T}{π ρ g}}$
$2 T l c o s θ = m g = π r^{2} l ρ g r = \sqrt{\frac{2 T}{π ρ g}}$

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A metallic wire of density ρ floats horizontal in water. The maximum radius of the wire so that the wire may not sink will be (Surface tension of water = T and angle of contact θ=0∘).

The correct option is A √2Tπρg2Tl cos θ=mg=πr2lρgr=√2Tπρg

A metallic wire of density $ρ$ floats horizontal in water. The maximum radius of the wire so that the wire may not sink will be (Surface tension of water = T and angle of contact $θ = 0^{\circ}) .$

The correct option is A
$\sqrt{\frac{2 T}{π ρ g}}$
$2 T l c o s θ = m g = π r^{2} l ρ g r = \sqrt{\frac{2 T}{π ρ g}}$