A metre rod of mass 1.2 kg is pivoted at one end and hangs vertically. It is displaced through an angle of 60. The increase in potential energy is (Given : g = 10 ms-2)
A
1 Joule
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B
1.5 Joule
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C
3 Joule
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D
6 Joule
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Solution
The correct option is D 3 Joule The mass of the rod is distributed all over its length. In such a situation, the entire mass can be considered to be concentrated at Its centre of gravity , which in this case is at mid point of the rod. As we can see from the figure the displacement in C.G is 1/4 m Therefore increase in its potential energy is given by, P=m∗g∗(1/4))=3J